Question

The equation of circle passing through (4, 5) and having the centre at (2, 2), is

• A. $x^2+y^2+4x+4y-5=0$
• B. $x^2+y^2-4x-4y-5=0$
• C. $x^2+y^2-4x=13$
• D. $x^2+y^2-4x-4y+5=0$

Answer 1

The correct option is B $x^2+y^2-4x-4y-5=0$

Centre (2, 2) and
R = $\sqrt{(4-2{)}^2+(5-2{)}^2}=\sqrt{13}$
Hence required equation is $x^2+y^2-4x-4y-5=0.$