The equation of circle passing through (4, 5) and having the centre at (2, 2), is

x^{2} + y^{2} + 4 x + 4 y - 5 = 0

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x^{2} + y^{2} - 4 x - 4 y - 5 = 0

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x^{2} + y^{2} - 4 x = 13

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x^{2} + y^{2} - 4 x - 4 y + 5 = 0

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Solution

The correct option is B $x^{2} + y^{2} - 4 x - 4 y - 5 = 0$
Centre (2, 2) and
R = $\sqrt{(4 - 2)^{2} + (5 - 2)^{2}} = \sqrt{13}$
Hence required equation is $x^{2} + y^{2} - 4 x - 4 y - 5 = 0.$

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