Question

# The equation of the circle which passes through the point (4, 5) and has its centre at (2, 2) is ____________.

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Solution

## Circle with center (2, 2) has equation of the form (x – 2)2 + (y – 2)2 = r2 (1) Since circle passes through (4, 5) ⇒ (4 – 2)2 + (5 – 2)2 = r2 i.e. 22 + 32 = r2 i.e. 4 + 9 = r2 i.e. r2 = 13 i.e. equation of circle is (x – 2)2 + (y – 2)2 = 13.

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