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Question

The equation of motion of a car is s=t22t, where is measured in hours and s in kilometres. When the distance travelled by a car is 15km, the velocity of the car is


A

2km/hr

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B

4km/hr

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C

3km/hr

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D

8km/hr

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Solution

The correct option is D

8km/hr


Step 1: Given Data:

Distances=15km

The equation for the motion of the car, s=t2-2t·····1

Step 2: Formula used:

Velocity is defined as rate of change of displacement. that is-

v=dsdt

Step 3: Calculation of the velocity of the car:

The distance travelled by car is 15km. Substitute the value of distance in equation 1 to obtain the time taken to travel this distance.

t2-2t=15t2-2t-15=0t2-5t+3t-15=0tt-5+3t-5=0t-5t+3=0t=5,-3

-3 can be neglected because time can't be negative. So

t=5hrs

Now differentiate the equation1 with respect to time to get the velocity.

dsdt=2t-2v=2t-2.......(2)

Substitute the value of t=5hrs in equation (2) to get the velocity-

v=2×5-2v=8kmhr

Hence, option D is the correct answer.


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