Question

The equation of motion of a projectile is
$y=12x-\frac{3}{4}{x}^2$
What is the range of the projectile?

• A. $12m$
• B. $16m$
• C. $20m$
• D. $24m$

Answer 1

The correct option is B $16m$

Horizontal Range of projectile means displacement covered by projectile in $x-$ axis.

Hence, during motion,

Initial level of projectile $=$ Final level of projectile

Hence, $y=0$ for finding range

Here,

$y=12x-\frac{3x^2}{4}$

put , $y=0$

$0=12x-\frac{3x^2}{4}$

$12x=\frac{3x}{4}$

$12\times 4=3x$

$x=16m$

Hence, range of projectile is $16m$