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Question

The equation of the line passing through (−4,3), parallel to the 3x+7y+6=0

A
3x+7y-9=0
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B
3x+7y+9=0
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C
3x+7y+3=0
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D
3x+7y+12=0
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Solution

The correct option is B 3x+7y-9=0
The line parallel to 3x+7y+6=0 is 3x+7y+k=0
It passes through (4,3)
3(4)+7(3)+k=012+21+k=0k=9
So the required equation is 3x+7y9=0

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