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Question

The equilibrium constant for the reaction
N2+2O22NO2
at a particular temperature is 100. Write down the equilibrium law equations of the following reactions and determine the values of equilibrium constants:
2NO2N2+2O2....(i)
NO21/2N2+O2...(ii)

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Solution

The equilibrium constant for the reaction
N2+2O22NO2
Kc=[NO2]2[N2][O2]2=100....(a)
The equilibrium constant equation for reaction (i)
K1=[N2][O2]2[NO2]2....(b)
This equation is reciprocal of eq. (a)
So, K1=1Kc=1100=1×102
The equilibrium constant equation for reaction (ii)
K2=[N2]1/2[O2][NO2]....(c)
Comparing eqs. (b) and (c)
K2=K1=102=101=0.1

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