wiz-icon
MyQuestionIcon
MyQuestionIcon
14
You visited us 14 times! Enjoying our articles? Unlock Full Access!
Question

The equilibrium mixture for formation of sulphur trioxide from sulphur dioxide present in 1 litre vessel at 600C contains 0.5, 0.12 and 5 mole of SO2, O2 and SO3.


A) Calculate Kc at 600C
B) Calculate Kp
C) How many moles of O2 must be forced into reaction vessel at 600C in order increase the concentration of SO3 to 5.2 moles?

A
83.3 mol1 lit1, 11.62 (atm)1 and 3.4 mole
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
833.33 mol1 lit1, 11.62 (atm)1 and 0.34 mole
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
8.33 mol1 lit1, 1.62 (atm)1 and 0.68 mole
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
83.33 mol1 lit1, 1.62 (atm)1 and 0.17 mole
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 833.33 mol1 lit1, 11.62 (atm)1 and 0.34 mole
The equilibrium reaction is 2SO2(g)+O2(g)2SO3(g).
The expression for the equilibrium constant is Kc=[SO3]2[SO2]2[O2].
Substitute values in the above expression.
(A) Kc=(5)2(0.5)2×0.12=833.33mol1lit

(B) Kp=Kc(RT)1=833.330.0821×873=11.62atm1

(C) Let x be the number of moles of oxygen that should be added.
Kc=(5.2)2(0.48)2×(0.12+x)=833.33mol1lit
Thus x=0.34 mole.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Equilibrium Constants
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon