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Question

The equilibrium mixture for formation of sulphur trioxide from sulphur dioxide present in 1 litre vessel at 600C contains 0.5, 0.12 and 5 mole of SO2, O2 and SO3.


A) Calculate Kc at 600C
B) Calculate Kp
C) How many moles of O2 must be forced into reaction vessel at 600C in order increase the concentration of SO3 to 5.2 moles?

A
83.3 mol1 lit1, 11.62 (atm)1 and 3.4 mole
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B
833.33 mol1 lit1, 11.62 (atm)1 and 0.34 mole
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C
8.33 mol1 lit1, 1.62 (atm)1 and 0.68 mole
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D
83.33 mol1 lit1, 1.62 (atm)1 and 0.17 mole
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Solution

The correct option is B 833.33 mol1 lit1, 11.62 (atm)1 and 0.34 mole
The equilibrium reaction is 2SO2(g)+O2(g)2SO3(g).
The expression for the equilibrium constant is Kc=[SO3]2[SO2]2[O2].
Substitute values in the above expression.
(A) Kc=(5)2(0.5)2×0.12=833.33mol1lit

(B) Kp=Kc(RT)1=833.330.0821×873=11.62atm1

(C) Let x be the number of moles of oxygen that should be added.
Kc=(5.2)2(0.48)2×(0.12+x)=833.33mol1lit
Thus x=0.34 mole.

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