Question

The equivalent mass of $KMn{O}_4$ in acidic medium is (molar mass of $KMn{O}_4$ = 158 g/mol)

• A. 158
• B. 15.8
• C. 31.6
• D. 3.16

Answer 1

The correct option is C

31.6

In acidic medium

The n-factor of $KMn{O}_4=5$ as it goes from +7 to the +2 state.

$\therefore$ Equivalent mass $=\frac{158}{5}$

= 31.6 g/equivalent