Question

The equivalent resistance between points $A$ and $B$ of the circuit given below is

Answer 1

$\frac{1}{R_{AB}}=\frac{1}{R}+\frac{1}{2R}+\frac{1}{2R}$

$\Rightarrow \frac{1}{R_{AB}}=\frac{2R+R+R}{2R^2}$

$\Rightarrow \frac{1}{R_{AB}}=\frac{4R}{2R^2}$

$\Rightarrow R_{AB}=\frac{R}{2}$