The equivalent weight of KIO3 in the reaction 2 CrOH3-4 OH-KIO3- 2CrO2-4-5H2O-KI is

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Balancing Redox Equations

The equivalen...

Question

The equivalent weight of $K I O_{3}$ in the reaction
$2 C r (O H)_{3} + 4 O H + K I O_{3} \to 2 C r O_{4}^{2 -} + 5 H_{2} O + K I$ is

Mole wt.

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\frac{M o l . w t .}{6}

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\frac{M o l . w t .}{2}

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\frac{M o l . w t .}{3}

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Solution

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K I O_{3}

2 C r (O H)_{3} + 4 O H + K I O_{3} \to 2 C r O_{4}^{2 -} + 5 H_{2} O + K I

K I O_{3}

2 C r (O H)_{3} + 4 O H + K I O_{3} \to 2 C r O_{4}^{2 -} + 5 H_{2} O + K I

2 C r (O H)_{3} + O H^{-} + K I O_{3} \to 2 C r O_{4}^{2 -} + 5 H_{2} O + K I

K I O_{3}

K I O_{3}

2 C r {(O H)}_{3} + O H^{-} + K I O_{3} ⟶ 2 C r O_{4}^{2 -} + K I + 5 H_{2} O

K I O_{3}

H C l

N_{2} H_{4} + I O_{3}^{-} + 2 H^{+} + C l^{-} \to I C I + N_{2} + 3 H_{2} O

N_{2} H_{4}

K I O_{3}

K I O_{3} = 214

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