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Oxyacids of Phosphorus

The equivalen...

Question

The equivalent weight of the underlined compound is $(80 + x)$ . Find the value of $x$ ________.
$N a H {C O}_{3} - --------- - + H C l ⟶ N a C l + H_{2} O + {C O}_{2}$

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Solution

In the given reaction, 1 mole of sodium hydrogen carbonate reacts with 1 mole of hydrogen ions.
Hence, the equivalent wight of sodium hydrogen carbonate will be equal to its molecular weight.
Equivalent weight of $N a {H C O}_{3} = \frac{m o l e c u l a r w e i g h t}{1} = \frac{84}{1} = 84$

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