Question

The expansion , $x^{logy-logz}.y^{logz-logx}.z^{logx-logy}$ when simplified reduces to...............

Answer 1

We have,

$x^{\log y-\log z}\cdot y^{\log z-\log x}\cdot z^{\log x-\log y}$

$=\frac{x^{\log y}}{x^{\log z}}\cdot \frac{y^{\log z}}{y^{\log x}}\cdot \frac{z^{\log x}}{z^{\log y}}$

$=1$

Hence, this is the answer.