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Standard XII

Chemistry

Depression in Freezing Point

The experimen...

Question

The experimental depression is freezing point of a dilute solution is 0.025 K. If the van't Hoff factor $i$ is 2.0, the calculated depression in freezing point (in K) is :

0.00125

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0.025

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0.0125

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0.05

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Solution

The correct option is B 0.0125
$i = \frac{(Δ T_{f}) o b s}{(Δ T_{f}) c a l}$

$2 = \frac{0.025}{(Δ T_{f}) c a l}$
$(Δ T_{f}) c a l = \frac{0.025}{2} = 0.0125$

Hence, option C is correct.

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The experimental depression is freezing point of a dilute solution is 0.025 K. If the van't Hoff factor i is 2.0, the calculated depression in freezing point (in K) is :

The correct option is B 0.0125i=(ΔTf)obs(ΔTf)cal 2=0.025(ΔTf)cal (ΔTf)cal=0.0252=0.0125Hence, option C is correct.

The experimental depression is freezing point of a dilute solution is 0.025 K. If the van't Hoff factor $i$ is 2.0, the calculated depression in freezing point (in K) is :

The correct option is B 0.0125
$i = \frac{(Δ T_{f}) o b s}{(Δ T_{f}) c a l}$

$2 = \frac{0.025}{(Δ T_{f}) c a l}$
$(Δ T_{f}) c a l = \frac{0.025}{2} = 0.0125$

Hence, option C is correct.