Question

The experimental value of dipole moment of HCl is 1.03 D. The length of H−Cl bond is 1.275 A. The percentage ionic character of HCl is:

• A. 43
• B. 21
• C. 17
• D. 7

Answer 1

The correct option is C 17

Percentage ionic character =μexpμcalc×100
μH−Cl=1.03 D=1.03×10−18 esu. cm
dH−Cl=1.275Ao=1.275×10−8 cm
Percentage ionic character=1.03×10−18(4.8×10−10 esu)×1.275×10−8×100=17%