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Question

The expression (x2+4y2−9z2)2−16x2y2, is equivalent to

A
(x2y+3z)(2x2y3z)(x2y+3z)(x+2y3z)
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B
(x+2y+3z)(x+2y+3z)(x2y+3z)(x+2y3z)
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C
(x2y+3z)(x+2y3z)(x2y+3z)(x2y3z)
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D
(x+2y+3z)(x+2y3z)(x2y+3z)(x2y3z)
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Solution

The correct option is D (x+2y+3z)(x+2y3z)(x2y+3z)(x2y3z)
(x2+4y29z2)216x2y2
=(x2+4y29z2)2(4xy)2
=(x2+4y29z2+4xy)(x2+4y29z24xy)
=(x2+4xy+4y2(3z)2)(x24xy+4y2(3z)2)
=(x2+2(x)(2y)+4y2(3z)2)(x22(x)(2y)+4y2(3z)2)
=((x+2y)2(3z)2)((x2y)2(3z)2)
=(x+2y+3z)(x+2y3z)(x2y+3z)(x2y3z)

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