The factorisation of $(4 x^{2} + 8 x + 3)$ is

(x + 1) (x + 3)

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(2 x + 1) (2 x + 3)

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(2 x + 2) (2 x + 5)

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(2 x - 1) (2 x + 3)

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Solution

The correct option is B $(2 x + 1) (2 x + 3)$
$4 x^{2} + 8 x + 3$

$\Rightarrow 4 x^{2} + 6 x + 2 x + 3$

$\Rightarrow 2 x (2 x + 3) + 1 (2 x + 3)$

$\Rightarrow (2 x + 3) (2 x + 1)$

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4 x^{2} + 8 x + 3

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Factorise $2 x^{2} - 7 x + 6$

\frac{x + 2}{(x + 1) (2 x + 3)} - \frac{2 x + 3}{(x + 1) (x + 2)} + \frac{3 x + 5}{(2 x + 3) (x + 2)}

$(4 x^{2} + 4 x - 3)$ =?

(a) $(2 x - 1) (2 x - 3)$

(b) $(2 x + 1) (2 x - 3)$

(d) None of these

x^{4} - 4 x^{2} + 12 x + 9

x^{2} + 2 x - 3

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