Question

The figure shows velocity-time graph of a stone thrown vertically upwards till it comes back to the ground. Find the total distance covered by the stone.

• A. $0$
• B. $80m$
• C. $160m$
• D. $240m$

Answer 1

Answer: (C)

$160m$

Total distance $=$ Area of ABO + Area of BDC $=\frac{1}{2}\times OA\times OB+\frac{1}{2}\times BD\times CD=(\frac{1}{2}\times 4\times 40)+(\frac{1}{2}\times 4\times 40)=160m$