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Reaction with Metals

The final pro...

Question

The final production in following sequence of reaction
$C H \equiv C H N a N H_{2} - ---- \to A C H_{3} B r - --- \to B$ :

C H_{2} = C H - C H = C H_{2}

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H C \equiv C - C H_{3}

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C H_{2} = C H - C H_{3}

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C H_{3} - C H_{2} - C H_{3}

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Solution

The correct option is B $H C \equiv C - C H_{3}$
$N a N H_{2}$ will deprotonated alkyne and then bromo methane will add a methyl group i.e Na will replaced to form propyne.

$C H \equiv C H + N a N H_{2} - --- \to - N H_{3} N a - C \equiv C - H C H_{3} B r - --- \to C H_{3} - C \equiv C - H + N a B r$

Hence, option $B$ is the answer.

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