You visited us 1 times! Enjoying our articles? Unlock Full Access!

Reaction with Metals

The final pro...

Question

The final production in following sequence of reaction
$C H \equiv C H N a N H_{2} - ---- \to A C H_{3} B r - --- \to B$ :

C H_{2} = C H - C H = C H_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H C \equiv C - C H_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C H_{2} = C H - C H_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} - C H_{2} - C H_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $H C \equiv C - C H_{3}$
$N a N H_{2}$ will deprotonated alkyne and then bromo methane will add a methyl group i.e Na will replaced to form propyne.

$C H \equiv C H + N a N H_{2} - --- \to - N H_{3} N a - C \equiv C - H C H_{3} B r - --- \to C H_{3} - C \equiv C - H + N a B r$

Hence, option $B$ is the answer.

Suggest Corrections

Similar questions

A g N O_{3}

C H_{3} - C H_{3}, C H_{2} = C H_{2}

C H \equiv C H

S_{N} 2

K I

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H ∣ C H_{3} - C H_{2} - C l

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{2} - C H_{2} - B r

(I) (I I)

C H_{3} - C H ∣ C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{3} ∣ C ∣ C H_{3} - C H_{2} C l

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - B r ∣ C H - C H_{3} a n d C H_{3} - C H_{3} ∣ C H - C H_{2} - B r ∣ C H - C H_{3}

(I) (I I)

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

Join BYJU'S Learning Program