The first ionisation potential of $A l$ is smaller than that of $M g$ because :

the atomic size of

A l > M g

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the atomic size of

A l < M g

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A l

has one unpaired electron in p-orbital

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the atomic number of

A l > M g

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Solution

The correct option is A $A l$ has one unpaired electron in p-orbital
It can be seen from the electronic configuration that, $A l$ have one unpaired electron in p orbital and $M g$ have two paired electron in s-orbitals, hence IP of $A l$ is low.

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Similar questions

The first ionization potential of Al is smaller than that of Mg because

A l

has lower ionization potential than that of

M g

because :

Q. First ionisation enthalpy of Al is lower than that of Mg. This is because:

The first ionistation enthalpies of Na, Mg, Al, and Si are in the order
(a) Na< Mg > Al < Si (b) Na> Mg > Al > Si
(c) Na< Mg< Al< Si (d) Na> Mg> Al < Si

Q. Arrange the elements S, N, Be, Mg and Al in the increasing order of their atomic size:

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The first ionisation potential of Al is smaller than that of Mg because :

The correct option is A Al has one unpaired electron in p-orbitalIt can be seen from the electronic configuration that, Al have one unpaired electron in p orbital and Mg have two paired electron in s-orbitals, hence IP of Al is low.

The first ionisation potential of $A l$ is smaller than that of $M g$ because :

The correct option is A $A l$ has one unpaired electron in p-orbital
It can be seen from the electronic configuration that, $A l$ have one unpaired electron in p orbital and $M g$ have two paired electron in s-orbitals, hence IP of $A l$ is low.