Question

The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor, if the cost per m² is Rs 4.

Answer 1

$$\begin{gathered} \mathrm{Given}: \\ \mathrm{The}\mathrm{floor}\mathrm{consist}\mathrm{of}3000\mathrm{rhombus}\mathrm{shaped}\mathrm{tiles}. \\ \mathrm{The}\mathrm{lengths}\mathrm{of}\mathrm{the}\mathrm{diagonals}\mathrm{of}\mathrm{each}\mathrm{tile}\mathrm{are}45\mathrm{cm}\mathrm{and}30\mathrm{cm}\text{.} \\ \therefore \mathrm{Area}\mathrm{of}\mathrm{a}\mathrm{rhombus}\mathrm{shaped}\mathrm{tile}=\frac{1}{2}\times (45\times 30)=675{\mathrm{cm}}^2 \\ \therefore \mathrm{Area}\mathrm{of}\mathrm{the}\mathrm{complete}\mathrm{floor}=3000\times 675=2025000{\mathrm{cm}}^2 \\ \mathrm{Now},\mathrm{we}\mathrm{need}\mathrm{to}\mathrm{convert}\mathrm{this}\mathrm{area}\mathrm{into}{\mathrm{m}}^2\mathrm{because}\mathrm{the}\mathrm{rate}\mathrm{of}\mathrm{polishing}\mathrm{is}\mathrm{given}\mathrm{as}\mathrm{per}{\mathrm{m}}^2. \\ \therefore 2025000{\mathrm{cm}}^2=2025000\times \mathrm{cm}\times \mathrm{cm} \\ =2025000\times \frac{1}{100}\mathrm{m}\times \frac{1}{100}\mathrm{m} \\ =202.5{\mathrm{m}}^2 \\ \mathrm{Now},\mathrm{the}\mathrm{cost}\mathrm{of}\mathrm{polishing}1{\mathrm{m}}^2\mathrm{is}\mathrm{Rs}4. \\ \therefore \mathrm{Total}\mathrm{cost}\mathrm{of}\mathrm{polishing}\mathrm{the}\mathrm{complete}\mathrm{floor}=202.5\times 4=810 \\ \mathrm{Thus},\mathrm{the}\mathrm{total}\mathrm{cost}\mathrm{of}\mathrm{polishing}\mathrm{the}\mathrm{floor}\mathrm{is}\mathrm{Rs}810. \end{gathered}$$