Question

The floor of a building consists of $3000$ tiles which are rhombus shaped and each of its diagonals are $45cm$ and $30cm$ in length. Find the total cost of polishing the floor, if the cost per $m^2$ is $euro4$.

Answer 1

Area of rhombus$=\frac{\text{product of diagonals}}{2}$

$=\frac{45\left(30\right)}{2}=675c{m}^2=0.0675m^2$
Total area of $3000$ tiles $=3000\left(0.0675\right)=202.5m^2$

Cost per $m^2=$ Rs. $4$
Cost of total cost of polishing the floor for $m^2=202.5\times 4$
$=$ Rs. $810$