Question

The floor of a building consists of $3000$ tiles which are rhombus shaped and each its diagonal are $45cm$ and $30cm$ in length find the total area of floor.

Answer 1

Area of rhombus$=\frac{pq}{2}$ where $p,q$ are the lengths of diagonal

Area of one tile $=\frac{\left(45\right)\left(30\right)}{2}$

Area of $3000$ tiles

$=3000\times \frac{\left(45\right)\left(30\right)}{2}$

$=2025000c{m}^2$.

Total area of floor is $2025000c{m}^2$.