Question

The floor of a building consists of $3000$ tiles which are rhombus shaped. The diagonals of each of the tiles are $45cm$ and $30cm.$ Find the total cost of polishing the floor, if cost per $m^2$ is $Rs.2.50.$

Answer 1

The diagonals of the rhombus are $45$ and $30$

The area of one tile is area of Rhombus having diagonal $d_1,d_2$ given by

$=\frac{1}{2}{d}_1\times d_2$

$=\frac{1}{2}\times 45\times 30=15\times 45=675c{m}^2$

Tha area of $3000$ such tiles is

$3000\times 6752025000c{m}^2$

$1c{m}^2={10}^{-4}{m}^{2}2025000c{m}^2=202.5m^2$

Cost of painting of area of $1m^2$ is $Rs.2.5$

Cost of painting of area of $202.5m^2$

$=2.5\times 202.5=Rs.506.25$

So the total cost for painting is $506.25Rs.$