The following equilibrium constants were determined at 1120 K-2COg - Cs- CO2g - KP1 - 10-14 atm-1COg - Cl2g - COCl2g- Kp2 - 6 - 10-3 atm-1What is the equilibrium constant KC for the following reaction at 1120 K-C s - CO2g - 2Cl2 g - 2COCl2g

C(s) + CO_2(g) ⇌ 2CO(g); K_p = 10^14atm 2CO(g) + 2Cl_2 (g) ⇌ 2COOCl_2 ; K_P_2 = (6 × 10^ 3)^2 atm^ 2 Add (1) and (2) C(s) + CO_2 + 2Cl_2(g) ⇌ 2COCl_2(g) ...

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Byju's Answer

Standard XIII

Chemistry

Characteristics of Equilibrium Constant

The following...

Question

The following equilibrium constants were determined at $1120 K$ :
$2 C O (g) ⇌ C (s) + C O_{2} (g); K_{P_{1}} = 10^{- 14} a t m^{- 1} C O (g) + C l_{2} (g) ⇌ C O C l_{2} (g); K_{p_{2}} = 6 \times 10^{- 3} a t m^{- 1}$
What is the equilibrium constant $K_{C}$ for the following reaction at $1120 K$ ;
$C (s) + C O_{2} (g) + 2 C l_{2} (g) ⇌ 2 C O C l_{2} (g)$

3.31 \times 10^{- 11} M^{- 1}

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5.5 \times 10^{10} M^{- 1}

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5.51 \times 10^{6} M^{- 1}

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None of these

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Solution

The correct option is A $3.31 \times 10^{- 11} M^{- 1}$
$C (s) + C O_{2} (g) ⇌ 2 C O (g); K_{p} = 10^{14} a t m 2 C O (g) + 2 C l_{2} (g) ⇌ 2 C O O C l_{2}; K_{P_{2}} = (6 \times 10^{- 3})^{2} a t m^{- 2}$
Add (1) and (2)
$C (s) + C O_{2} + 2 C l_{2} (g) ⇌ 2 C O C l_{2} (g) K_{p} = 10^{14} \times 36 \times 10^{- 6} = 36 \times 10^{8} a t m^{- 1}$
We know that $K_{p} = K_{c} \times (R T)^{Δ n_{g}} K_{c} = K_{p} \times (R T)^{- Δ n_{g}}$
For given reaction $Δ n_{g} = - 1 ∴ K_{c} = K_{p} (R T) = 36 \times 10^{8} a t m^{- 1} \times 0.0821 L a t m K^{- 1} m o l^{- 1} \times 1120 K_{c} = 3.31 \times 10^{11} M^{- 1}$

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Similar questions

Q. The following equilibrium constants were determined at 1120 K:

2 C O (g) ⇌ C (s) + C O_{2} (g) K p_{1} = 10^{- 14} a t m^{- 1}

C O (g) + C l_{2} (g) ⇌ C O C l_{2} K p_{2} = 6 \times 10^{- 3} a t m^{- 1}

What is the equilibrium constant

K_{p}

for the following reaction at 1120 K.

C (s) + C O_{2} (g) + 2 C l_{2} (g) ⇌ 2 C O C l_{2} (g)

Q. The following equilibrium constants were determined at

1120 K

2 C O (g) ⇌ C (s) + C O_{2} (g); K_{p 1} = 10^{- 14} {atm}^{- 1}

C O (g) + C l_{2} (g) ⇌ C O C l_{2} (g); K_{p 2} = 6 \times 10^{- 3} {atm}^{- 1}

What is the equilibrium constant

K_{P}

for the following reaction at same temperature?

C (s) + C O_{2} (g) + 2 C l_{2} (g) ⇌ 2 C O C l_{2} (g)

Q. The following equilibrium constants were determined at

1120 K

2 C O (g) ⇌ C (s) + {C O}_{2} (g); K_{p_{1}} = 10^{- 14} {a t m}^{- 1}

C O (g) + C l_{2} (g) ⇌ C O {C l}_{2} (g); K_{p_{2}} = {6 \times 10}^{- 3} {a t m}^{- 1}

What is the equilibrium constant

K_{c}

for the following reaction at

1120 K

C (s) + {C O}_{2} (g) + 2 C l_{2} (g) ⇌ 2 C O {C l}_{2} (g)

Q. Given,

2 C O (g) ⇌ C (s) + C O_{2} (g); K_{p_{1}} = 10^{- 14} a t m^{- 1}

1120 K

C O (g) + C l_{2} (g) ⇌ C O C l_{2} (g); K_{p_{2}} = 6 \times 10^{- 3} a t m^{- 1}

The value of

K_{c}

for the following reaction at

1120 K

will be?

C (s) + C O_{2} (g) + 2 C l_{2} (g) ⇌ 2 C O C l_{2} (g)

The following equilibrium constants were determined at $1120 K$ :
$2 C O (g)$ ⇌ $C (s) + C O_{2} (g)$ ; $K_{p_{1}} = 10^{- 14} a t m^{- 1}$
$C O (g) + C l_{2} (g)$ ⇌ $C O C l_{2} (g); K_{p_{2}} = 6 \times 10^{- 3} a t m^{- 1}$

What is the equilibrium constant $K_{C}$ for the following reaction at $1120 K$ ;

$C (s) + C O_{2} (g) + 2 C l_{2} (g) ⇌ 2 C O C l_{2} (g)$

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The following equilibrium constants were determined at 1120 K: 2CO(g)⇌C(s)+CO2(g); KP1=10−14atm−1CO(g)+Cl2(g)⇌COCl2(g); Kp2=6×10−3atm−1 What is the equilibrium constant KC for the following reaction at 1120 K; C(s)+CO2(g)+2Cl2(g)⇌2COCl2(g)