Question

The following side reaction in the production of $N_2{H}_4$

$N_2{H}_4+2N{H}_{2}Cl⟶N_2+2N{H}_{4}Cl$ :

• A. is catalysed by traces of heavy metals as $C{u}^{2+}$
• B. is suppressed by addition of gelation or glue
• C. is made reversible by removing $N_2$
• D. is made reversible by adding $NaOH$

Answer 1

Answer: (A), (B)

The correct options are
A is catalysed by traces of heavy metals as $C{u}^{2+}$
B is suppressed by addition of gelation or glue

$\begin{array}{c}\text{Cu+2 acts as catalytic substance while}\text{glue can act as catalytic poison, as it retards the}\\ \text{rate of reaction.}\\ \text{By the Le-chateliers principle, here after removing}{N}_2\text{,}\text{reaction further becomes forward and hence cannot}\\ \text{reverse back.}\end{array}$