The force acting on a charge q moving with a velocity V in a magnetic field of induction B is given by :
A
q→V×→B
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B
→V×→Bq
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C
q(→V×→B)
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D
(→V.→B)q
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Solution
The correct option is Aq(→V×→B) The magnetic force on a free moving charge is perpendicular to both the velocity of the charge and the magnetic field with direction given by the right hand rule . The force is given by the charge times the vector product of velocity and magnetic field.