The force experienced by a chloride ion having $4$ electrons removed, when placed in an electric field of intensity $2 N C^{- 1}$ is :

12.8 \times 10^{- 19} N

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12.8 \times 10^{- 16} N

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6.4 \times 10^{- 19} N

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6.4 \times 10^{- 16} N

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Solution

The correct option is A $12.8 \times 10^{- 19} N$
When $4 e^{-}$ are removed charge on chloride ion
$= 4 \times 1 \cdot 6 \times 10^{- 19} C .$
Now $F = E q$
$= 2 \times 4 \times 1 \cdot 6 \times 10^{- 19}$
$F = 12 \cdot 8 \times 10^{- 19} N$

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The force experienced by a chloride ion having 4 electrons removed, when placed in an electric field of intensity 2NC−1 is :

The correct option is A 12.8×10−19NWhen 4e− are removed charge on chloride ion=4×1⋅6×10−19C.Now F=Eq=2×4×1⋅6×10−19F=12⋅8×10−19N

The force experienced by a chloride ion having $4$ electrons removed, when placed in an electric field of intensity $2 N C^{- 1}$ is :

The correct option is A $12.8 \times 10^{- 19} N$
When $4 e^{-}$ are removed charge on chloride ion
$= 4 \times 1 \cdot 6 \times 10^{- 19} C .$
Now $F = E q$
$= 2 \times 4 \times 1 \cdot 6 \times 10^{- 19}$
$F = 12 \cdot 8 \times 10^{- 19} N$