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Question

The freezing point of a solution prepared from 1.25 g of non-electrolyte and 20 g of water is 271.9K. If the molar depression constant is 1.86Kmol1, then molar mass of the solute will be:

A
105.7
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B
106.7
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C
115.3
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D
93
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Solution

The correct option is D 93
ΔTf=1000Kf×W2Mw2×W1

[ΔT=273271.9=1.25]

1.25=1000×1.86×1.25Mw2×20

Mw2=93

Hence, the correct option is D

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