Question

The freezing point of a solution prepared from 1.25 g of non-electrolyte and 20 g of water is 271.9K. If the molar depression constant is $$1.86\, K\, {mol}^{-1}$$, then molar mass of the solute will be:

A
105.7
B
106.7
C
115.3
D
93

Solution

The correct option is D 93$$\Delta {T}_{f}=\displaystyle\frac{1000{K}_{f}\times {W}_{2}}{M{w}_{2}\times {W}_{1}}$$$$[\Delta T=273-271.9=1.25]$$$$1.25=\displaystyle\frac{1000\times 1.86\times 1.25}{M{w}_{2}\times 20}$$$$M{w}_{2}=93$$Hence, the correct option is $$D$$Chemistry

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