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Question

The freezing point of a solution prepared from 1.25 g of non-electrolyte and 20 g of water is 271.9K. If the molar depression constant is $$1.86\, K\, {mol}^{-1}$$, then molar mass of the solute will be:


A
105.7
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B
106.7
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C
115.3
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D
93
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Solution

The correct option is D 93
$$\Delta {T}_{f}=\displaystyle\frac{1000{K}_{f}\times {W}_{2}}{M{w}_{2}\times {W}_{1}}$$

$$ [\Delta T=273-271.9=1.25]$$

$$1.25=\displaystyle\frac{1000\times 1.86\times 1.25}{M{w}_{2}\times 20}$$

$$M{w}_{2}=93$$

Hence, the correct option is $$D$$

Chemistry

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