The frictional force of the air on a body of mass $0.25 k g$ , falling with an acceleration of $9.2 {m / s}^{2}$ , will be:

1.0 N

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0.55 N

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0.25 N

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0.15 N

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Solution

The correct option is B $0.15 N$
$F = m g - f_{f r i c t i o n a l} = m a$
$F = 0.25 \times 9.8 - f_{f r i c t i o n a l} = 0.25 \times 9.2$
$f_{f r i c t i o n a l} = 0.15 N$

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