The frictional force of the air on a body of mass $0.25 k g$ , falling with an acceleration of $9.2 m / s^{2}$ , will be :

1.0 N

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0.55 N

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0.25 N

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0.15 N

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Solution

The correct option is D $0.15 N$
net force on the body $F = m g - r e s i s t a n c e = m g - f$
$0.25 \times 9.8 - f = 0.25 \times 9.2$
$f = 0.25 \times 0.6 = 0.15 N$

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