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Question

The function f:RR given by f(x)=cosx for all xR, is :

A
surjective bu nor injective
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B
injective but nor surjective
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C
neither injective nor surjective
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D
injective
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Solution

The correct option is C neither injective nor surjective
Injectivity : We know that f(0)=cos0=1 and f(2π)=cos2π=1.
So, different elements in R may have the same image. Hence, f is not an injection.
Surjectivity : Since the values of cosx lie between 1 and 1, it follows that the range of f(x) is not equal to its co-domain. So, f is not a surjection.

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