CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The function f:RR given by f(x)=cosx for all xR, is :

A
surjective bu nor injective
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
injective but nor surjective
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
neither injective nor surjective
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
injective
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C neither injective nor surjective
Injectivity : We know that f(0)=cos0=1 and f(2π)=cos2π=1.
So, different elements in R may have the same image. Hence, f is not an injection.
Surjectivity : Since the values of cosx lie between 1 and 1, it follows that the range of f(x) is not equal to its co-domain. So, f is not a surjection.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Animal Tissues
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon