The green colour produced in the borax bead test of a chromium (III) salt is due to:

C r B

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C r_{2} O_{3}

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C r_{2} (B_{4} O_{7})_{3}

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C r (B O_{2})_{3}

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Solution

The correct option is D $C r (B O_{2})_{3}$
The corresponding reactions are:
$N a_{2} B_{4} O_{7} \cdot 10 H_{2} O Δ - \to N a_{2} B_{4} O_{7} + 10 H_{2} O (↑) Δ - \to 2 N a B O_{2} + B_{2} O_{3}$
$C r_{2} (S O_{4})_{3} + 3 B_{2} O_{3} ⟶ 2 C r (B O_{2})_{3} (g r e e n c o l o u r b e a d) + 3 S O_{3}$

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