The highest magnetic moment is shown by

N i

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C o

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F e

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S c

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Solution

The correct option is C $F e$
The expression for magnetic moment is $μ = \sqrt{n (n + 2)}$ , where $n$ is the number of unpaired electrons. Greater is the number of unpaired electrons, greater is the magnetic moment. $S c, N i, F e$ and $C o$ have $1, 2, 4$ and $3$ electrons respectively. Therefore, $F e$ has the highest magnetic moment.

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Similar questions

C o = 27, N i = 28]

Magnetic moment of which ion is 2.88 BM ?

M^{2 +}

Z n^{2 +} > S c^{2 +} = C u^{2 +} > T i^{2 +} = N i^{2 +} > V^{2 +} = C o^{2 +} > C r^{2 +} = F e^{2 +} > M n^{2 +}

[F e (H_{2} O)_{6}]^{2 +}

[F e (C N)_{6}]^{4 -}

[N i (C O)_{4}]

[N i (H_{2} O)_{4}]^{2 +}

[N i (C N)_{4}]^{2 -}

[F e (H_{2} O)_{6}]^{2 +}

[F e (C N)_{6}]^{4 -}

[N i (C O)_{4}]

[N i (H_{2} O)_{4}]^{2 +}

[N i (C N)_{4}]^{2 -}

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