The horizontal force needed to move the crate of $50 k g$ on a rough horizontal surface . Given the coefficient of static friction is $0.5$ .

25 N

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50 N

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125 N

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250 N

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500 N

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Solution

The correct option is D $250 N$
Given : $m = 50 k g$ $μ = 0.5$
Horizontal force needed $F = f_{m a x} = μ m g$
$∴$ $F = 0.5 \times 50 \times 10 = 250$ $N$

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The horizontal force needed to move the crate of 50kg on a rough horizontal surface . Given the coefficient of static friction is 0.5.

The correct option is D 250NGiven : m=50kg μ=0.5Horizontal force needed F=fmax=μmg∴ F=0.5×50×10=250 N

The horizontal force needed to move the crate of $50 k g$ on a rough horizontal surface . Given the coefficient of static friction is $0.5$ .

The correct option is D $250 N$
Given : $m = 50 k g$ $μ = 0.5$
Horizontal force needed $F = f_{m a x} = μ m g$
$∴$ $F = 0.5 \times 50 \times 10 = 250$ $N$