The hybridisationof Bromine in $B r F_{5}$ molecule is:

s p^{3} d

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s p^{3} d^{3}

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s p^{3}

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s p^{3} d^{2}

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Solution

The correct option is C $s p^{3} d^{2}$
$B r$ in bromine pentafluroide has $5$ bond pairs and $1$ lone pair and so, the hybridisation would be $s p^{3} d^{2}$ .

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Similar questions

X e F_{2}, X e F_{3}^{+}, X e F_{4}, X e F_{6}

What is the hybridization of P in $P C l_{5} (s)$ ?

$M o l e c u l e H y b r i d i s a t i o n S h a p e$

$A . P O_{4}^{- 3} 1. s p^{2} a) D i s t o r t e d o c t a h e d r a l$

$B . X e F_{6} 2. s p^{3} b) P y r a m i d$

$C . S O_{3}^{- 2} 3. s p^{3} d c) T e t r a h e d r a l$

$D . N O_{3}^{- 1} 4. s p^{3} d^{3} d) T r i a n g u l a r p l a n a r$

The correct match is

In solid state of $P C l_{5}$ , the hybridsation of 'P'is

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