Question

The hybridization states of the central atom in the complexes $\left[Fe\right(CN{)}_6{]}^{3-},\left[Fe\right(CN{)}_6{]}^{4-}$ and $\left[Co\right(N{O}_2{)}_6{]}^{3-}$ are

• A. $d^{2}s{p}^3,s{p}^3{d}^2$ and $ds{p}^2$ respectively
• B. $d^{2}s{p}^3,s{p}^3{d}^2$ and $s{p}^3{d}^2$ respectively
• C. $d^{2}s{p}^3,s{p}^3{d}^2$ and $d^{2}s{p}^3$ respectively
• D. all $d^{2}s{p}^3$

Answer 1

The correct option is D all $d^{2}s{p}^3$

The central metal ions in the complexes $\left[Fe\right(CN{)}_6{]}^{3-},\left[Fe\right(CN{)}_6{]}^{4-}and\left[Co\right(N{O}_2{)}_6{]}^{3-}$ undergo $d^{2}s{p}^3$ hybridization to form inner orbital complexes with octahedral geometry.

Hence the correct option is D.