Question

The intercepts made by the line $2x-3y+12=0$ on the co-ordinate axis are

• A. $x-$ intercept $=-6$ and $y-$ intercept $=4$
• B. $x-$ intercept $=4$ and $y-$ intercept $=-6$
• C. $x-$ intercept $=-3$ and $y-$ intercept $=2$
• D. None of these

Answer 1

Answer: (A)

$x-$ intercept $=-6$ and $y-$ intercept $=4$

Given line equation is $2x-3y+12=0$

On putting $y=0$, we will get the intercept made on x - axis

$2x-3y+12=0$

$2x-3\times 0+12=0$,

$2x-0+2=0$,

$2x=-12$

$\Rightarrow x=-6$

Now, on putting $x=0$, we get the intercepts made on y - axis

$2x-3y+12=0$

$2\times 0-3y+12=0$

$-3y=-12$

$\Rightarrow y=4$

Hence, the x - intercept and y - intercept of the given line is $-6$ and $4$ respectively.