The internal resistance of a primary cell is 4 Ω. It generates a current of 0.2 A in an external resistance of 21Ω. The rate of chemical energy consumed in providing the current is
A
0.42Js−1
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B
0.84Js−1
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C
1Js−1
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D
5Js−1
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Solution
The correct option is C1Js−1 By conservation of energy. Chemical energy consumed per sec =heat energy produced per sec=I2(R+r)=(0.2)2(21+4)=1Js−1