Question

The ionic conductivity of $B{a}^{2+}$ and $C{l}^{-}$ at infinite dilution are $127$ and $76{\text{ohm}}^{-1}c{m}^{2}mo{l}^{-1}$ respectively .The equivalent conductivity of $BaC{l}_2$ at infinity dilution $({\text{in ohm}}^{-1}c{m}^{2}e{q}^{-1}$) would be :

• A. $279$
• B. $203$
• C. $139.5$
• D. $101.5$

Answer 1

The correct option is C $139.5$

Correct option :B

The equivalent weight of $BaC{l}_2=\frac{\text{molecular weight}}{2}$


Equivalent conductivity of $\left(BaC{l}_2\right),{\Lambda }_m^{\infty }=\frac{1}{2}{\lambda }_m^{\infty }\left(B{a}^{2+}\right)+{\lambda }_m^{\infty }\left(C{l}^{-}\right)$
$=63.5+76=139.5{\text{ohm}}^{-1}c{m}^{2}e{q}^{-1}$