The ionisation energy of hydrogen atom is $13.6$ eV. What will be the ionisation energy of $H e^{+}$ ?

13.6

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54.4

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122.4

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Zero

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Solution

The correct option is B $54.4$ eV
Ionisation energy of $H e^{+} = 13.6 \times Z^{2}$ eV

$= 13.6 \times (2)^{2}$ eV

$= 13.6 \times 4$ eV $=$ $54.4$ eV.

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