The latent heat of fusion of ice is:
(a) 33.4 ×105J/Kg (b) 22.5 ×105J/Kg (c) 33.4 ×104J/Kg (d) 2.25 ×104J/Kg
What is meant by saying that the latent heat of vaporisation of water is 22.5×105J/Kg?
2000 J of heat is required to melt 40 Kg of substance, then the specific latent heat of substance is
Why is the latent heat of fusion of ice i.e 3.34×105 J/kg less than the latent heat of vapourisation i.e 22.5×105 J/kg? Particles of solids are more tightly packed than liquids so literally the should require more energy for separation than liquids.
A lead ball at 30 ∘C is dropped from a height of 6.2 km. The ball is heated due to the air resistance and it completely melts just before reaching the ground. The molten substance falls slowly on the ground. Calculate the latent heat of fusion of lead. Specific heat capacity of lead = 126 J kg−1 ∘C−1 and melting point of lead = 330 ∘C. Assume that any mechanical energy lost is used to heat the ball. Use g = 10 ms−2.