The length of a hall is 18 m and its width is 13.5 m. Find the least number of square tiles, each of side 25 cm, required to cover the floor of the hall,
(1) without leaving any margin
(2) leaving a margin of width 1.5 m all around.
In each case,find the cost of the tiles required at the rate of ₹ 6 per tile.

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Solution

Length of the hall = 18m = 1800cm
the width = 13.5m = 1350cm

area of floor = 1800x1350 = 2430000cm²

area of tile = 25x25 = 625cm²

1. No. of tiles (without leaving any margin) = 2430000/625 = 3888

2. the width of margin = 1.5m = 150cm
new length = 1800-2x150 = 1500cm
new width = 1350-2x150= 1050
new area = 1500x1050 = 1,575,000
no. of tiles = 1575000/625 = 2520

3. Cost in the first case = 3888x6 = 23,328 rupees
Cost in the 2nd case = 2520x6 =15,120 rupees

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