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Perimeter of a Triangle

The length of...

Question

The length of a rectangle is $10 m$ more than its breadth. if the perimeter of rectangle is $80 m$ . find the dimensions and area of the rectangle.

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Solution

$\begin{matrix} L e t t h e b r e a d t h = x c m l e n g t h = x + 10 P e r i m e t e r = 80 m 2 (l + b) = 80 m l + b = 40 x + 10 + x = 40 x = 15 c m t h e n, l e n g t h = 15 + 10 = 25 l = 25 c m D i m e n s i o n (l, b) = (25 c m, 15 c m) a r e a = l \times b = 25 \times 15 = 375 c m^{2} \end{matrix}$

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