Question

The length of a rectangle is $16m$ more than its breadth. If the perimeter of the rectangle is $56m$. Find its length and breadth.

Answer 1

Let the length of the rectange os $x$ m. The breadth of the rectangle be $(x-16)m$.

Now we have

Perimeter of the rectangle $=56m$

$\Rightarrow$ $2(length+breadth)=56$

$\Rightarrow$ $2x+(x-16)=56$

$\Rightarrow$ $2(2x-16)=56$

$\Rightarrow$ $4x-32=56+32$

$\Rightarrow$ $4x=56+32$

$\Rightarrow$ $4x=88$

$\Rightarrow$ $x=\frac{88}{4}$

$=22m$

$\therefore$ the length of the rectangle $=22m$ and the breadth of the rectangle $=(x-16)m$

$=(22-16)m$

$=6m$

Hence, the length and breadth of the rectangle are $22m$ and $6m$ respectively.