Question

The length of the diagonal of a rectangle is $40$ cm. If the length of its shorter side is $24$ cm, find the area of the rectangle(in $c{m}^2$).

Answer 1

Let the length of the diagonal be d and sides of the rectangle be a and b

Thus, $d^2=a^2+b^2$

${40}^2={24}^2+b^2$

$1600=576+b^2$

$1024=b^2$

$b=32cm$

Length of longer side = 32 cm

Area of rectangle = length X breadth

Area of rectangle = $32\times 24$

Area of rectangle =$768c{m}^2$