The length of the rectangle is greater than its breadth by 2 cm. The area of the rectangle is 24 sq.cm, find its length.

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Solution

Let the length of rectangle be $l$ and breadth be $b$
Then, $l - b = 2$ or $l = b + 2$ ........(1)
Area of rectangle is $24$
$∴ l b = 24$
$b (b + 2) = 24$ ...............From (1)
$b^{2} + 2 b - 24 = 0$
$b^{2} + 6 b - 4 b - 24 = 0$
$(b + 6) (b - 4) = 0$
$b = - 6, 4$
Taking only positive value, $b = 4$ .
Hence, breadth is $4$ cm and length is $6$ cm.

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The length of the rectangle is greater than its breadth by 2 cm. The area of the rectangle is 24 sq.cm, find its length.

Let the length of rectangle be l and breadth be bThen, l−b=2 or l=b+2........(1)Area of rectangle is 24∴lb=24b(b+2)=24...............From (1)b2+2b−24=0b2+6b−4b−24=0(b+6)(b−4)=0b=−6,4Taking only positive value, b=4.Hence, breadth is 4 cm and length is 6 cm.