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Byju's Answer
Standard XII
Physics
Work Done When Force Is Varying
The mass equi...
Question
The mass equivalent of 931.5 MeV energy is
A
1.66
×
10
−
27
k
g
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B
6.02
×
10
−
24
k
g
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C
1.66
×
10
−
20
k
g
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D
6.02
×
10
−
27
k
g
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Solution
The correct option is
A
1.66
×
10
−
27
k
g
According to Einstein, mass energy equivalence is represented by
E
=
m
C
2
Taking
m
=
1
a
.
m
.
u
=
1.66
×
10
−
27
㎏
and
C
=
3
×
10
8
㎧
We get
E
=
1.66
×
10
−
27
×
(
3
×
10
8
)
2
J
=
1.49
×
10
−
10
J
As
1
M
e
V
=
1.6
×
10
−
13
J
∴
E
=
1.49
×
10
−
10
1.6
×
10
−
13
E
=
931.25
M
e
V
Hence the mass equivalent of
931.25
M
e
V
energy is
1.66
×
10
−
27
㎏
Suggest Corrections
0
Similar questions
Q.
Using
E
=
m
c
2
, find out the energy released, when
2
u
of mass is destroyed completely.
Take
1
u
=
1.66
×
10
−
27
k
g
.
Q.
A neutron breaks into a proton and an electron. Calculate the energy produced in this reaction is MeV. Mass of an electron
=
9
×
10
−
31
k
g
, mass of proton
=
1.6725
×
10
−
27
k
g
, mass of neutron
=
1.6747
×
10
−
27
k
g
, and speed of light
=
3
×
10
8
m
s
−
1
Q.
Assume that a molecule is moving with the root mean square speed at temperature 300 K. The de Broglie wavelength of nitrogen molecule is (Atomic mass of nitrogen = 14.0076 u, h =
6.63
×
10
−
27
J
s
,
k
B
=
1.38
×
10
−
23
J
K
−
1
,
1
u
=
1.66
.
×
10
−
27
k
g
)
Q.
A nitrogen molecule has two nitrogen atoms separated by a distance of
1.3
×
10
−
10
m
. Find its moment of inertia about the centre of mass. If its rational kinetic energy is
4
×
10
−
21
J
. Then compute its frequency of rotation about the centre of mass. the mass of a nitrogen atom is
14
amu (
1
amu
=
1.66
×
10
−
27
k
g
)
Q.
Assume that a neutron breaks into a proton and an electron. The energy released during this process is : (mass of neutron
=
1.6725
×
10
−
27
k
g
, mass of proton
=
1.6725
×
10
−
27
k
g
, mass of electron
=
9
×
10
−
31
k
g
)
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