Question

The mass of $2.24\times {10}^{-3}{m}^3$ of a gas is $4.4g$ at $273.15K$ and $101.325kPa$ pressure.

The gas may be :

• A. $NO$
• B. $N{O}_2$
• C. $C_3{H}_8$
• D. $N{H}_3$

Answer 1

Answer: (C)

$C_3{H}_8$

Applying ideal gas equation,
$\text{pV = nRT}$
or $pV=\frac{m}{M}RT$
$M=\frac{mRT}{pV}$
$=\frac{4.4\times 8.314\times 273.15}{101.325\times {10}^3\times 2.24\times {10}^{-3}}$
$=44.01\approx 44gmo{l}^{-1}$
Hence, the gas is $C_3{H}_8$