The mass of an electron is 9.1×10−31kg. If the K.E. is given as 3.0×10−25J. Calculate the wavelength of the electron.
A
8967oA
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B
6242oA
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C
7264oA
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D
6966oA
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Solution
The correct option is A8967oA K.E.=12mv2-----(1) λ=hmv v=hmλ ----(2) By eq. (1) and (2), K.E.=12m(hmλ)2 λ=√h22mK.E =√(6.626×10−34)22×9.1×10−31kg×3.0×10−25J =8967×10−7m=8967oA