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Question

The mass of an electron is 9.1×1031 kg. If the K.E. is given as 3.0×1025 J. Calculate the wavelength of the electron.

A
8967oA
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B
6242oA
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C
7264oA
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D
6966oA
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Solution

The correct option is A 8967oA
K.E.=12mv2-----(1)
λ=hmv
v=hmλ ----(2)
By eq. (1) and (2),
K.E.=12m(hmλ)2
λ=h22m K.E
=(6.626×1034)22×9.1×1031kg×3.0×1025J
=8967×107m=8967oA

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